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Plane would need to go 200mph ground speed with a tail wind of 100mph. If it were to take off.. (remember the theoretical planes take off speed on a windless day was 100mph air speed) |
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2 cars head on at 60mph is a combined speed of 120mph. A bit like 1 car going 120mph and hitting a stationary car. It must be possible to understand the plane thing. Forward motion comes from the jet engine/props. The wheels are only there to keep its belly off the ground. Here's another question. If the treadmill only spins to match the force from the wheels.... would the treadmill need to spin at all if the plane was being powered forward by a jet. Would the wheels just roll over the top without exerting force on the treadmill? |
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you have 120mph of force/engergy or what ever you call it, and it is divided into 2 cars. So each car gets 60mph of damage. So it should be the same as hitting a solid wall at 60 also. Yeah and the plane on treadmill is so blatantly obvious to me now i dont know why i needed to ask in the first place. Think of the plane being pulled off the belt by a winch, the winch does not need to pull the plane faster or with any more force regardless of is its on a conveyer belt or the ground. The plane pulls its self through the air and thus has nothing to do with the ground. Plane is driven forward by the air it displaces - so only effected by wind speed, not ground speed A car is driven forward by its wheels - so is effected by ground speed A rocket is driven upwards by pure thrust - so is only effected by gravity and air resistance |
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BTW, how's the watch working out? Forgot, the horse would lose because it'd be dead http://www.discussworldissues.com/fo...ilies/sad1.gif |
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Its like one car going 30mph hitting a stationary object. |
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I'm still lolling at this. OK....think about this. Kinetic energy is generated by any object that is moving. When that object suddenly stops that energy has to be dissipated. If two moving objects collide then both sets of kinetic energy have to be dissipated. If a moving object collides with a stationary object both can share the dissipation of the kinetic energy. http://en.wikipedia.org/wiki/Collision |
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They originally claimed the same as you. Loads of viewers wrote in and complained saying they were wrong. They tested it - they were wrong. 2 cars at 30 mph hitting each other head on is the same as one car hitting a wall at 30mph. EDIT: Here is a decent explanation: http://warp.povusers.org/grrr/collisionmath.html |
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look. 2 cars head on at 60mph =120mph of force. divide that force between the 2 cars and you have 60mph of force being afflicted to each car. Both cars are smashed up the same as if they would have hit a solid unbreakable wall at 60mph. because the solid wall does not absorb any of the force, so the car gets the full 60mph of damage. Its so obvious its easyer to understand than the plane thing. 2 cars at 60 = 120 they hit each other, the force is divided by 2. Each car get same damage as 60mph if hitting a solid wall. thanks for insulting me Quantumdefect, when actually its blatantly obvious you are wrong. :D |
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You cant magically get both cars getting a force of a 240mph if they are both going 60mph. 2 x 60 = 120 not 240. 120 / 2 = 60.... |
No. Two cars, each travelling at 30mph towards each other, colliding is theoretically the same as one car travelling at 60mph hitting a stationary object. Yes, the physics makes it clear that the impact velocity of two head-on objects will be viewed from the perspective of any one of the objects as being a collision equating to double the object's velocity. It's basic relativity, after all. However, impacts are about forces. In the case of each object in the collision, their change in momentum is not a change in relative momentum but an absolute one. So a 1000 kg car doing 20 m/s will have a momentum of 20,000 kgm/s and so if the impact time is 2 seconds, for example, that equates to an impact force of 10 kN and not 20 kN.
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Divide 120 between the 2 cars, and you get 60. So a car going 60 and hitting a solid unbreakable wall = 60mph divided by 1. 2x60/2=60 1x60/1=60 |
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StonedOne, you aren't understanding it either, just getting the correct result through incorrect reasoning. |
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(2) Government and road safety campaigns have always maintained that head-on collisions are the worst accident to have. While this may be true, it's not, of course, due to the collision velocity being doubled but it's about the surrounding environment, e.g. other vehicles colliding with the impact vehicles and so on. |
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