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**derisgun** · 03-14-2009, 11:07 PM

I see the point about the step where essentially there is a div/0.

Isn't there however an actual algebraic error done prior which is what allowed that situation?

I think it lies along these lines.....b does not equal the square root of b^2.

03-14-2009, 11:07 PM	#19
derisgun Join Date Nov 2005 Posts 426 Senior Member	I see the point about the step where essentially there is a div/0. Isn't there however an actual algebraic error done prior which is what allowed that situation? I think it lies along these lines.....b does not equal the square root of b^2.
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