General Discussion Undecided where to post - do it here. |
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#6 |
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That's a funny way of saying it.
Obviously the solution doesn't have to be polynomial. Yes it does, that's guaranteed by how I got q and r and p. PLUS, the q[x+1] in the notation is unneeded as far as I can tell, since you might as well assume it's q[x]. It's needed when you know the origin of those three polynomials. (For context, I'm performing Gosper's algorithm to find the closed form of a hypergeometric sum, if it exists. This is just one step.) |
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