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Old 09-16-2010, 05:32 PM   #61
BypeVupyide

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Care to draw a diagram?

I am confused.
I'm not going to get away with a picture, so let's do this in right hand cartesian, with x vertical.

Brown's coordinate system is centered relative to Pink at (3,0,0) in centimetres, with p and b notation indicating the system in use.

Vectors point away from recipient.

C1 = -ip
C2 = ib + jb - kb
C3 = ib - jb - kb

That should give you a rough idea.
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Old 09-16-2010, 05:32 PM   #62
Alkanyadela

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It's not supposed to be anything, I was just thinking with that wide load it would be easier for her to cowboy one guy whilst getting two in the shitter. The other way round has feet near faces.

I knew what I meant.
[rofl][rofl]
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Old 09-16-2010, 08:11 PM   #63
teodaschwartia

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I'm not going to get away with a picture, so let's do this in right hand cartesian, with x vertical.

Brown's coordinate system is centered relative to Pink at (3,0,0) in centimetres, with p and b notation indicating the system in use.

Vectors point away from recipient.

C1 = -ip
C2 = ib + jb - kb
C3 = ib - jb - kb

That should give you a rough idea.
Are we assuming that the recipient is laying along the +z axis, facing in the direction of +x? If so, C1 has to be well-endowed, or there is a beam-crossing violation occurring.

That is a huge no-no.
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Old 09-16-2010, 08:48 PM   #64
Alkanyadela

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I'm not going to get away with a picture, so let's do this in right hand cartesian, with x vertical.

Brown's coordinate system is centered relative to Pink at (3,0,0) in centimetres, with p and b notation indicating the system in use.

Vectors point away from recipient.

C1 = -ip
C2 = ib + jb - kb
C3 = ib - jb - kb

That should give you a rough idea.
So a bit like this??

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Old 09-16-2010, 08:55 PM   #65
Garry Richardson

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she looks quite good, but most latin girls are such a hassle it's not worth it... Thinking they rule the earth and all and if you disagree with their opinions they act like you stabbed them and won't talk to you unless you beg them to.. I'm generalizing of course, but the really good looking latin girls are like that.. Actually most good looking women are like that unfortunately

And going into a locker room with a sexy outfit (saw some footage) what was she expecting??? She looked like she was paid for by one of the fans
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Old 09-16-2010, 09:18 PM   #66
BypeVupyide

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Are we assuming that the recipient is laying along the +z axis, facing in the direction of +x? If so, C1 has to be well-endowed, or there is a beam-crossing violation occurring.

That is a huge no-no.
Recipient's spine is +z, facing -x, hence brown being above pink. C1 strikes from below.

I'm now visualising this in spherical polar and it's making me hard.
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Old 09-16-2010, 09:52 PM   #67
teodaschwartia

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hence brown being above pink.
Ding ding ding. That is the kicker!

I spend too much time with black women where the color codes are tastefully reversed.[rofl]
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Old 09-16-2010, 09:56 PM   #68
lh88gFzI

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Ding ding ding. That is the kicker!

I spend too much time with black women where the color codes are tastefully reversed.[rofl]
This is also true.

I had to draw out the coordinates system on a notepad to visualize what quantum was refering to. I must be getting rusty.
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