LOGO
General Discussion Undecided where to post - do it here.

Reply to Thread New Thread
Old 03-15-2007, 08:19 AM   #1
agracias

Join Date
Oct 2005
Posts
391
Senior Member
Default A Little Math Help
I need help on this if any of you can knock it out i would really appreciate it.

Here is the problem

There is house that is 1621 square feet. Someone is having the entire floor covered in 2 different tiles. One of the tiles is 20inch by 20inch. Another tile is 6inch by 6inch. The two tiles will create a pattern (i will do my best to draw this out)

http://mnetcs.com/thumb/?reference=dock&imageid=841
how many of each type tile do you need to cover 1621 square feet (12inch x 12inch is a square foot for my metric brothers]
can anyone figure out this problem... i am no math wiz, though i am sure this is a simple problem... been a while since i graduated college and though i took many a mathmatics course and even did well in them, once done i wiped that section of my brain clean [surrender]

thanks in advance!
agracias is offline


Old 03-15-2007, 08:36 AM   #2
Zfdeisde

Join Date
Nov 2005
Posts
420
Senior Member
Default
What's the pattern look like?
Zfdeisde is offline


Old 03-15-2007, 08:50 AM   #3
agracias

Join Date
Oct 2005
Posts
391
Senior Member
Default
What's the pattern look like?
should be working now... sorry, it worked before in the preview to the post

dammit... now sometimes i get a red square, but if you click it it will pop up right...damn resizer
agracias is offline


Old 03-15-2007, 12:59 PM   #4
agracias

Join Date
Oct 2005
Posts
391
Senior Member
Default
is no one good at math either.... i need to buy this stuff tomorrow morning
agracias is offline


Old 03-15-2007, 02:16 PM   #5
THOUTHCAW

Join Date
Oct 2005
Posts
389
Senior Member
Default
LOL, well I'm pretty sure my method is ****, but in case you're wondering...

The pattern in your image covers an area of about 5*(20/12)^2 + 4*(6/12)^2 = 134/9 sq feet

So the number of sets of that pattern you need to cover 1621 sq feet is about 1621/(134/9) = 108.873

...rounding that up, say you need 109 sets. In each set there are 5 big tiles, and 4 small tiles. So my simple brain says okay buy at least 109*5 big tiles and 109*4 small tiles. In other words, 545 big tiles and 436 small tiles.

Like I said, my 5 minute calculation is shitty :P
THOUTHCAW is offline


Old 03-15-2007, 02:51 PM   #6
agracias

Join Date
Oct 2005
Posts
391
Senior Member
Default
LOL, well I'm pretty sure my method is ****, but in case you're wondering...

The pattern in your image covers an area of about 5*(20/12)^2 + 4*(6/12)^2 = 134/9 sq feet

So the number of sets of that pattern you need to cover 1621 sq feet is about 1621/(134/9) = 108.873

...rounding that up, say you need 109 sets. In each set there are 5 big tiles, and 4 small tiles. So my simple brain says okay buy at least 109*5 big tiles and 109*4 small tiles. In other words, 545 big tiles and 436 small tiles.

Like I said, my 5 minute calculation is shitty :P
thanks for the answer...can anyone back these numbers up?
agracias is offline


Old 03-15-2007, 03:03 PM   #7
mikeyyuiok

Join Date
Oct 2005
Posts
502
Senior Member
Default
This is a repeating pattern of two tiles,one 20"x20" and one 6"x6", total area for the pattern is therefore 436 square inches.
Area of floor is 1621 square feet which is 233424 square inches.

For the number of pattern sets, 233424/436 = 535.376. As you cannot order a partial square, round them both up to 536 of each.
Note, this assumes the tiles are trimmed to suit and the cut off pieces are re-used for the spaces between the full size squares and the edges, but as the floor shape hasn't been given, I would assume this was the case.
mikeyyuiok is offline


Old 03-15-2007, 03:09 PM   #8
agracias

Join Date
Oct 2005
Posts
391
Senior Member
Default
This is a repeating pattern of two tiles,one 20"x20" and one 6"x6", total area for the pattern is therefore 436 square inches.
Area of floor is 1621 square feet which is 233424 square inches.

For the number of pattern sets, 233424/436 = 535.376. As you cannot order a partial square, round them both up to 536 of each.
Note, this assumes the tiles are trimmed to suit and the cut off pieces are re-used for the spaces between the full size squares and the edges, but as the floor shape hasn't been given, I would assume this was the case.
ok...that is correct...the cut off pieces will be used on corners and around the wall.... but i guess i do not understand the outcome of your solution.... you are saying I only need 56 of each tile to cover the floor

well you edited it as i was typing... so 536 of each tile?
agracias is offline


Old 03-15-2007, 03:11 PM   #9
THOUTHCAW

Join Date
Oct 2005
Posts
389
Senior Member
Default
Gordo corrected his math error, and I agree with his more logical breakdown of the pattern.
THOUTHCAW is offline


Old 03-15-2007, 03:23 PM   #10
agracias

Join Date
Oct 2005
Posts
391
Senior Member
Default
Gordo corrected his math error, and I agree with his more logical breakdown of the pattern.
lemme see if i got this right???

Since in the pattern there will either be one large piece surrounded by 4 smaller pieces or 1 smaller piece surrounded by 4 larger pieces... depending on how you look at it... the number of each piece required should be the same... so...

(536*20*20/12)/12=1488.88=1489.0 sf
(536*6*6/12)/12=134

1489+134=1623 which is perfect....thank you very much!
agracias is offline



Reply to Thread New Thread

« Previous Thread | Next Thread »

Currently Active Users Viewing This Thread: 1 (0 members and 1 guests)
 

All times are GMT +1. The time now is 04:19 PM.
Copyright ©2000 - 2012, Jelsoft Enterprises Ltd.
Search Engine Friendly URLs by vBSEO 3.6.0 PL2
Design & Developed by Amodity.com
Copyright© Amodity